Sometimes an analysis of a file's contents is helpful. A Java method can be used to read in a file, count letters, and display the results.
Let us first consider the example text file. It contains some patterns of letters like 2 "x" characters and one uppercase Z.
This program uses BufferedReader
and HashMap
. With BufferedReader
, it reads in a file line-by-line. We then loop over the line and call charAt
to access characters.
char
in the HashMap
.getOrDefault
to get an existing value from the HashMap
or 0. Then we put one plus that value.for
-loop on the result of keySet()
. We display all characters found and their frequencies in the file.import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; import java.util.HashMap; public class Program { public static void main(String[] args) throws IOException { HashMap<Integer, Integer> hash = new HashMap<>(); // Load this text file. BufferedReader reader = new BufferedReader(new FileReader( "C:\\programs\\file.txt")); while (true) { String line = reader.readLine(); if (line == null) { break; } for (int i = 0; i < line.length(); i++) { char c = line.charAt(i); if (c != ' ') { // Increment existing value in HashMap. // ... Start with zero if no key exists. int value = hash.getOrDefault((int) c, 0); hash.put((int) c, value + 1); } } } // Close object. reader.close(); // Display values of all keys. for (int key : hash.keySet()) { System.out.println((char) key + ": " + hash.get(key)); } } }aaaa bbbbb aaaa bbbbb aaaa bbbbb CCcc xx y y y y y Za: 12 b: 15 C: 2 c: 2 x: 2 y: 5 Z: 1
For performance, an array of all possible char
values can be used. We can use a char
as an index by casting it to an int
. Then we increment each char
index as it is encountered.
With some inspection, we can see that the results of the program are correct. This kind of program will need to be modified to suit your exact goals. But the general approach is durable.
Often in programs we can use a HashMap
to count how often an element occurs. It is possible to increment the value on each encountered key.