Convert `String`, Integer

A String can be converted to an Integer. The String stores the digits of a number. Some functions available do not handle invalid cases well.

We show the Integer.TryParse method as a solution to handling invalid data. It does not cause performance problems with exceptions.

Here, the input String is correctly formatted. It contains the number "123456" stored as characters. We declare the local variable "i" and then use Integer.TryParse in an If-expression.

Info After Integer.TryParse returns True, we have an actual Integer. We show this by dividing the Integer by two.

And This would not be possible with a number stored in String format. A string cannot be divided.

Module Module1
    Sub Main()
        ' Input String.
        Dim value As String = "123456"

        ' Use Integer.TryParse.
        Dim i As Integer
        If (Integer.TryParse(value, i)) Then
            Console.WriteLine("Integer: {0}", i)
            Console.WriteLine("Half:    {0}", i / 2)
        End If
    End Sub
End ModuleInteger: 123456
Half:    61728

Discussion

Integer.TryParse does not cause performance problems when an invalid number is encountered. This method is usually considered the best parsing method.

Also You do not have to write custom algorithms. TryParse will tell you if you have an invalid number.

Detail Integer.TryParse is probably best unless you have serious performance demands.

We converted a String holding digit characters into an actual Integer. Integer.TryParse (and other TryParse functions) is versatile and useful.

Convert String, Integer

Discussion

Convert `String`, Integer