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VB.NET DateTime Examples

Use DateTime in programs. Access DateTime constructors and properties.

DateTime.

This Structure represents a point in time. It stores times, like 12 AM, and dates like yesterday. With TimeSpan we capture time differences.TimeSpan

Features.

Methods are used to compute relative times such as yesterday and tomorrow. DateTime can be formatted—this changes it to a String.Format

New instance.

A DateTime instance can be created with the New operator. There are many overloads. But the overload shown here accepts 3 arguments.

Arguments: The arguments here are the year, the month, and the day of that month. The value 2 stands for February.

Warning: If you pass an invalid argument (one that no date could have), you will get an ArgumentOutOfRangeException.

VB.NET program that uses constructor Module Module1 Sub Main() Dim value As DateTime = New DateTime(2017, 2, 1) ' Display the date. Console.WriteLine(value) ' Test the year. If value.Year = 2017 Then Console.WriteLine("Year is 2017") End If End Sub End Module Output 2/1/2017 12:00:00 AM Year is 2017

Yesterday.

To get yesterday, we can access the Today property and then add negative one days to it. This is equivalent to subtracting one day from the DateTime instance.		VB.NET program that computes yesterday Module Module1 Sub Main() ' Write the today value. Console.WriteLine("Today: {0}", DateTime.Today) ' Subtract one day. Dim yesterday As DateTime = DateTime.Today.AddDays(-1) ' Write the yesterday value. Console.WriteLine("Yesterday: {0}", yesterday) End Sub End Module Output Today: 1/17/2010 12:00:00 AM Yesterday: 1/16/2010 12:00:00 AM

Tomorrow.

This is a good day to schedule less pleasurable tasks. To compute tomorrow, we add one day with Add Days() on the value returned by the Today property.

Note: The output of the program will be different depending on when you run it.

VB.NET program that computes tomorrow Module Module1 Sub Main() ' Write Today. Console.WriteLine("Today: {0}", DateTime.Today) ' Add one to Today to get tomorrow. Dim tomorrow As DateTime = DateTime.Today.AddDays(1) ' Write. Console.WriteLine("Tomorrow: {0}", tomorrow) End Sub End Module Output Today: 1/17/2010 12:00:00 AM Tomorrow: 1/18/2010 12:00:00 AM

First day.

Getting the first day in a year is useful. We defines two new methods to get the first day in a year. When no argument is specified, the current year (for Today) is used.		VB.NET program that finds first day Module Module1 Sub Main() ' Write first day of current year. Console.WriteLine("First day: {0}", FirstDayOfYear) ' Write first day of 1999. Dim y As New DateTime(1999, 6, 1) Console.WriteLine("First day of 1999: {0}", FirstDayOfYear(y)) End Sub ''' <summary> ''' Get first day of the current year. ''' </summary> Private Function FirstDayOfYear() As DateTime Return FirstDayOfYear(DateTime.Today) End Function ''' <summary> ''' Get first day of the specified year. ''' </summary> Private Function FirstDayOfYear(ByVal y As DateTime) As DateTime Return New DateTime(y.Year, 1, 1) End Function End Module Output First day: 1/1/2010 12:00:00 AM First day of 1999: 1/1/1999 12:00:00 AM

Last day.

Here we compute the last day in a year. This may help with year-based record keeping. The method gets the first day of the next year, and then subtracts one day.

Tip: Please see also the IsLeapYear Function, which can tell us whether an additional day is in the year or not.

VB.NET program that computes last day Module Module1 Sub Main() ' Write current last day. Console.WriteLine("Last day: {0}", LastDayOfYear) ' Write last day of 1999. Dim d As New DateTime(1999, 6, 1) Console.WriteLine("Last day of 1999: {0}", LastDayOfYear(d)) End Sub ''' <summary> ''' Get last day of the current year. ''' </summary> Private Function LastDayOfYear() As DateTime Return LastDayOfYear(DateTime.Today) End Function ''' <summary> ''' Get last day of the specified year. ''' </summary> Private Function LastDayOfYear(ByVal d As DateTime) As DateTime Dim time As New DateTime((d.Year + 1), 1, 1) Return time.AddDays(-1) End Function End Module Output Last day: 12/31/2010 12:00:00 AM Last day of 1999: 12/31/1999 12:00:00 AM

DaysInMonth.

Months contain different numbers of days. With the shared DaysInMonth Function, we get day-counts for a month in a specific year. The 2 means February.		VB.NET program that uses DaysInMonth Module Module1 Sub Main() ' There are 28 days in February. Dim count As Integer = DateTime.DaysInMonth(2014, 2) Console.WriteLine(count) ' Count days in March of 2014. Dim count2 As Integer = DateTime.DaysInMonth(2014, 3) Console.WriteLine(count2) End Sub End Module Output 28 31

Get DayOfWeek.

Every day in the future of our universe will have a day of week—like Monday or Tuesday. If you have a special day you need to test for, use the DayOfWeek property.

Info: This property returns a DayOfWeek Enum value. We can test it against a DayOfWeek enumerated constant.

Enum		VB.NET program that gets day of week Module Module1 Sub Main() ' Get current day of the week. Dim day As DayOfWeek = DateTime.Today.DayOfWeek ' Write the current day. Console.WriteLine("TODAY IS {0}", day) End Sub End Module Output TODAY IS Wednesday

DateString.

This property, only offered in VB.NET, returns the current date in String representation. Usually, DateTime-based methods are preferable—they are more standard.

Internals: DateString simply accesses the Today property on DateTime, and then it calls ToString with a format string.

Tip: Many global functions in the VB.NET language are implemented with the standard .NET libraries.

VB.NET program that uses DateString Module Module1 Sub Main() Console.WriteLine(DateString) End Sub End Module Output 05-18-2011

Date.

This is another VB.NET special type. It aliases the DateTime type and has all the same methods. We can use Date interchangeably with DateTime.

Note: Usually DateTime is preferred in .NET programs as it is standard—all C# programs use DateTime not Date.

VB.NET program that uses Date type Module Module1 Sub Main() ' The Date type is the same as the DateTime type. Dim d As Date = New Date(2014, 10, 6) Dim d2 As DateTime = New DateTime(2014, 10, 6) If d = d2 Then Console.WriteLine("Equal dates") End If End Sub End Module Output Equal dates

Error, un-representable.

We cannot create a DateTime that cannot possibly exist. Here we try to use a month of 20 in the constructor, but get an "un-representable" error.Exception		VB.NET program that shows parameter error Module Module1 Sub Main() ' Cannot have a month of 20, no such month exists. Dim value As DateTime = New DateTime(2000, 20, 1) End Sub End Module Output Unhandled Exception: System.ArgumentOutOfRangeException: Year, Month, and Day parameters describe an un-representable DateTime. at System.DateTime.DateToTicks(Int32 year, Int32 month, Int32 day) at System.DateTime..ctor(Int32 year, Int32 month, Int32 day)...

Now property.

This property is the same as Today, but it fills in the time. So it represents both the current time and the current date—Today just represents the current date.DateTime.Now

Parse.

DateTime.Parse converts a string to a DateTime. If we read in string data from user input or a database, we can parse it into a DateTime for further processing.DateTime.Parse

Timing.

Timers are excellent for checking up on your program with a diagnostic method. They can execute any code. We can, for example, run a Timer every 30 seconds.TimerStopwatchBenchmarks

TimeZone.

Day light changes, and time zones, can be complex. With the TimeZone.CurrentTimeZone property we access information that can help some programs.TimeZone

A helpful type.

We used the DateTime type in the VB.NET language in some specific, useful ways. The examples provide an overall glimpse into the DateTime type but not a comprehensive view.
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